That is a very simple mathematics question.7 v# o# m6 B# r1 e$ E
Let x = Male, y = Female, z = Child
5 o% G$ f5 z/ f+ e+ s- ?6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb3 ^5 k# z4 w* D$ ^* u' V
x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ s0 J* p& k5 [0 O
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
# t! ]5 Q+ K, v: {$ nSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4: V' `6 G: e; s, u3 ]
Formula 4 can change into 11x + 5y = 100 Formula 5www3.tvboxnow.com+ o! s6 S) @3 j0 y0 ]0 t
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.! Q4 r- e" y" F1 W, o
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
+ z# C" _: b* r8 q! Y% }; `Eventually, the answer is 20 female and 80 children and no male. |