That is a very simple mathematics question.
, {- H8 D" w; E' Y- U+ RLet x = Male, y = Female, z = Child
9 h H0 a* ]) N+ o6 @tvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
3 {9 @* _( u2 {6 f Lx + y + z = 100 Formula 2
0 P0 t: g" d$ J1 Z2 l公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
& b& S% o& I5 z8 F3 U" s! `2 i: W公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
' ~3 G3 {5 Q- L* oTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5. \9 L$ B- T# @3 j6 e c* a
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.7 a0 b, h* q. X Y0 P+ y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 K# ]0 k# l- B
Eventually, the answer is 20 female and 80 children and no male. |