hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^$ T: f+ k" Q$ x8 y$ h# U1 P& y
1st u divide the ball into two group (i group 6 ball)
, G# E3 k1 u- D7 o; o6 I" G$ U( rwww3.tvboxnow.comthen 称 them c which side is the heavy
+ B( \1 d6 O; y; `: iwww3.tvboxnow.comthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
8 ~( T- T0 P1 C2 L) ~! gwww3.tvboxnow.comif not balance take the heavy and then 1 M" U7 ?- A* W" k% L  s- n' Z
take the heavy group divided into 2 group i group contain 1 ball than 称 it
, `' `: G! W: Y公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇. d. Y' n) e! s8 O6 y. K
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边2 |0 J" r6 |3 s7 M4 V7 Y
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me