zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次公仔箱論壇1 x8 e4 s1 G  H* n4 Z
将比较重的那份再平均分成两份成一次9 F4 x8 r. {5 P* S; A1 B
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
% k/ d1 a0 _( z, ]tvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight
! D8 s" z( m. x. K2 a    then goto 2 - compare rest of(4)  - 2 with 2
4 k" x- ?# Q$ c           if (left side is more weight)
0 ^8 O8 Y5 K7 Y$ _; Lwww3.tvboxnow.com              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
2 I6 }" I6 t  b: L6 ]! R: Owww3.tvboxnow.com          else ( right side is more weight)
8 ]& V3 @* |% G4 ^" j' ]$ I, c              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
" A# n$ W4 u8 R7 j8 N# c* A$ Xwww3.tvboxnow.comelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。