1. divide 6 and 6, both sides will not equal& ]# f5 n' `/ C$ b a8 X5 o8 E
2. take any side of the 6, divide then 3 and 3, again both sides will not equal: V& I/ |( v' m( s/ [
3. take any 2 and weigh them 6 P) Y4 H# z! K: z! L) l0 x# M! xtvb now,tvbnow,bttvbif they equal, the one left is the ball.