" B9 L$ X- d1 Y& ]; [) O" H/ xWhy an integer, that is greater than six and is between two prime numbers, can be always divided by six? (5,6,7; 11,12,13; 17,18,19; 29,30,31; etc) + B% j1 |; `3 H( dwww3.tvboxnow.com* s f4 X% L* t8 a' a0 }
Answer will be provided on Sunday (19 Sept 2010)..作者: idontlikeapple 時間: 2010-9-18 08:26 PM
/ g; p0 N1 @* u0 v: O3 eIt is because that prime number is always an odd number, so the next number is always a even number that is dividable by two. In addition, every three number in a sequence, there must be an integer that is dividable by three. If a sequence of three integers contains two prime numbers and an integer, and that integer must be dividable by three. That integer is both dividable by two and three, thus, dividable by six.
