6 X+ P. |9 H/ vTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。答案：結果是只可能大家一起死。無論怎麼拿1號都是死的，所以怎麼樣他都得拖人下水，1號會拿20個，結果是前4個都拿20個，最後一個拿幾個都一樣，大家一起死。www3.tvboxnow.com& A; @) u0 V x. B
, g" P: }; J' v2 G9 y$ [7 e( i
[ 本帖最後由 蘭昀 於 2007-3-7 05:11 PM 編輯 ]作者: CrAzY_FoG 時間: 2006-12-5 10:43 AM 標題: err
no.2? cos he can counts how many no1 took from the bag....only a quick guess作者: CrAzY_FoG 時間: 2006-12-5 10:54 AM 標題: sorry forgot explain
if no1 took 50, the bag left 50, then no 2 takes 25 the must be in between, if no1 took 30, bag the bag left 70, take 29...etc,作者: ManGuy 時間: 2006-12-5 12:26 PM
da answer is NO.5 coz he don't hv to do anything n da first 4 people is die already...................作者: jerry1900 時間: 2006-12-6 12:55 AM
Don't kow作者: sitsky 時間: 2006-12-6 05:44 PM
they will all die becuz they will each get 20作者: 聖誕島 時間: 2006-12-6 05:58 PM
真係好難作者: hke777 時間: 2006-12-6 11:25 PM
>:D< 開估啦 !作者: roylife 時間: 2006-12-7 11:38 AM
NO.1 ,NO3 AND NO4作者: wagonwagon 時間: 2006-12-7 02:30 PM
有难度，慢慢想作者: ryanfumin 時間: 2006-12-7 07:04 PM
why作者: fisher11 時間: 2006-12-7 07:58 PM
好好想想！作者: APN 時間: 2006-12-8 05:12 AM
I had a quick guess, is No.1. + e% F1 }; @( v# m- _Because what ever he or she taken, the next person will take what ever had taken with +1 or -1 to ensure they havn't got the same number. at the end, no1 will had the most likely middle number and without a same number. of coz he will need to pick a number from 3 to 19.作者: chen_329 時間: 2006-12-8 10:44 AM
i don't know作者: b40342 時間: 2006-12-8 02:14 PM
看来我的智商确实比较低，乖乖的等答案吧！ :'(作者: fishy129 時間: 2006-12-9 12:41 AM
number 4 has the best chance to live ; L1 S, T, t! E1 a& h9 V7 F. zassume number 1, 2, 3 and 4, pick number a, b, c and d. ; `, Q. `( i; P* y, N4 X" xtvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-c ; ? D* [* J5 J8 B; D3 sTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。take the average of (100-a-b-c)5 q) F+ g8 @, y1 I. N
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)6 t% o5 y$ m- c( v( Y( |% X
and number 4 can squeeze himself into the average and what number 5 picks.tvb now,tvbnow,bttvb0 A0 Q) A1 T: u$ G; Q6 f, {8 [) V
so number 4 will have the best chance. 3 T* V& i) G# U5 g* [. j+ k . I2 l! W) U5 ^" ^i hope this is a good logic hehe作者: kyle326 時間: 2006-12-12 12:47 PM
no 2 !!! no 2 !!! www3.tvboxnow.com, }0 W/ b; |: I3 e8 P3 |+ l
6 k" [# I8 c+ A O' n$ WTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18. www3.tvboxnow.com5 w+ W( A4 s& e2 W: K2 B
So they will all die !! 6 k0 s; K& B/ U# ]8 `: P . y) S2 p/ w; Z6 b& `& MTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。8 M3 O* p- P/ ?! u: w6 d6 f
www3.tvboxnow.com, w ^' ]' S% @* _
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans. ; W# k! G* U8 F% e. a* fwww3.tvboxnow.com % |2 j) r; t+ G: H- \TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. ; M! B/ O; t- ^tvb now,tvbnow,bttvb u1 e4 o1 f4 d* Y; W) R2 _" g) d
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.3 g% A" d3 ^8 _: H; Y
3 U+ J6 B$ X% w! ?. a/ [tvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20 y G9 P6 r6 B- L8 N7 Wtvb now,tvbnow,bttvb - S% N8 h d6 o( F, A4 @$ [* S#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.+ h+ k# Z) V- B5 c0 X9 j W0 Q% b+ k
$ J G$ S/ R% t9 f" Q& fwww3.tvboxnow.com#5 same as above, he takes 80 divided by 4 =20, picked 20 as well. / h: g; y/ g# O x7 K3 m o% ~9 L) b: R# Y
Ended all have the same number and all died.作者: chester1109 時間: 2006-12-15 12:36 AM
我猜NO4，1 r* D6 N! c- k# \! v: ?' U: L
因為他可以取前面三位豆子的平均數， 9 @1 s' e B# }- h: k9 O* c: W也可以防止豆子不夠讓NO5墊底。作者: 289675283 時間: 2006-12-15 01:19 AM
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅3 m& j. D6 G% b) N9 ~5 v$ ^
aiya, how come still no answer ga.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。0 I/ j1 E: z; h3 f4 Y
please post answer la, G$ [& P) n' ~( n- @
can't wait la作者: wenz 時間: 2006-12-16 09:28 PM
不知道啊作者: pokekugai 時間: 2006-12-17 11:36 AM
i think # 3 will be the one to survive..knowing what the first two take and what 's left for the last two to pick will give him a better chance to live.作者: ahkhang 時間: 2006-12-18 04:13 AM
too difficult !!作者: IDentity 時間: 2006-12-18 04:25 AM
唔识作者: Kaya 時間: 2006-12-18 04:54 AM
no 4 i guess作者: funhunter 時間: 2006-12-18 01:05 PM
2作者: kyfung 時間: 2006-12-20 09:31 PM
2nd one作者: qrl888 時間: 2006-12-21 08:51 PM
不知道作者: fxenon 時間: 2006-12-21 11:08 PM
no1, take19,等no2之後的互相猜忌...........死都死3,4,5號先啦作者: kakashi 時間: 2006-12-22 09:55 AM
真係好難作者: baby坦克 時間: 2006-12-22 01:59 PM
too diffcult!作者: kkqmg 時間: 2006-12-22 11:57 PM
就是这么难作者: ptv 時間: 2006-12-23 12:03 AM
$-) $-) $-)作者: ivan123 時間: 2006-12-26 04:39 PM
123作者: clj 時間: 2006-12-26 06:36 PM
should be no2?? choose number that is less than the first one while greater than "leftover beans"/3. Which control wht no.3 & 4 &5 chooses ) E; X: v& n, n9 Q/ l* ]/ C9 ]( M: f
If no.1 takes very little bean.. e.g. 3 beans.. then no.2 just take one more than him.. bcos when the forth and fifth person is choosing, they should not be able to guess easily wht no.2 has chosen....if no.1 takes 3 beans.. (the logically minimum... since nobody will choose 1... and therefore 2 is the minmum that a normal person will choose... but since equilvalent is dead as well.. minimum will choose is 3).. then no.2 will take 4 beans.. no.3 should be able to tell that one person chose 3 & 4 beans and is highly likely to choose 4 too and hope that 4 &5 choose higher since it is harder to guess the highest and lowest when the numbers are so close together. Therefore no.2 should be the best position???作者: haocao 時間: 2006-12-27 08:38 AM
no.2作者: 魔戒 時間: 2006-12-27 09:15 AM
NO.3 RIGHT?作者: cclaa 時間: 2006-12-27 10:43 PM
I would guess No.4~~couse he quite a lots choose to make no. 5 die~~~like only leave 2 beans at the bag~~when the bag is on No.4's hand and it ONLY got 49 OR LESS beans~~he will sure win~~~作者: cclaa 時間: 2006-12-27 10:55 PM
Sorry~~that's wrong answer~~misunderstanding the Question~~~sorry~~~作者: cclaa 時間: 2006-12-27 11:44 PM
no. 4 tvb now,tvbnow,bttvb _# E' `" t* x" i
其實照睇機率no.3都好大~~因為佢有最大能力control no.4 n 5~~because when the bag is on No.3's hand and it ONLY got 57 OR LESS beans~~he will sure win~~~but As 他們都是很聰明的人~~~第一個就唔會咁順灘咁簡多beans~~~如果佢簡好少beans~~like 10 or something(唔想計exactly幾多~haha)~~~~因為2,3,4 都係靠低過佢1粒再逼no.5 點簡都死~~~而no1簡拎少既話~其他人有可能成為最低要死果個~~而佢地都唔會點簡相同數目~~~因為冇point咁做(想同人一齊死就會)~~咁第4個就可以簡前3個人既平均數~~咁就一定中間~~希望岩啦~~~^^作者: rickysome0 時間: 2006-12-28 12:21 AM
no4作者: j_hf_cheung 時間: 2006-12-28 01:56 PM
no one dies作者: yth 時間: 2006-12-31 07:15 AM
提示: 作者被禁止或刪除 內容自動屏蔽作者: yth 時間: 2006-12-31 07:33 AM
提示: 作者被禁止或刪除 內容自動屏蔽作者: yth 時間: 2007-1-1 04:48 AM
提示: 作者被禁止或刪除 內容自動屏蔽作者: Shet 時間: 2007-1-1 08:40 AM
first 1 took 22, second 21, third 20, fourth 19, third 18. so these they wont have the same number of beans, of course 2 of them 5 have to die coz they got biggest n smaller number. seriously idk what is the question want us to answer? is it want them 5 all alive or 2 have them have to sarcarfice?作者: keiko1124 時間: 2007-1-1 03:51 PM
睇下ans~先!作者: xyxfish 時間: 2007-1-1 06:47 PM
i wanna see the answer[-O< [-O<作者: diamond王子 時間: 2007-1-1 11:23 PM
so hard~~ 2 i7 n; X: o0 btvb now,tvbnow,bttvbthxthx作者: benny0077 時間: 2007-1-2 04:11 AM
難作者: 打爆寶礦力 時間: 2007-1-4 02:10 AM
發了ans沒?作者: AhChow 時間: 2007-1-4 03:58 AM
really tough..作者: messy 時間: 2007-1-4 10:22 AM
No2作者: muimuikw 時間: 2007-1-4 12:31 PM
應該係第一個安全，佢拎96顆淨番4顆俾其餘4個人，佢地一定要拎一顆。 / Z5 j. T b% h3 @0 D9 Jpt4，若有重復的情況，則也算最大或最小，一併處死; x0 u2 i% U: i1 v* A甘即係2，3，4，5都係得一顆算係最大甘96咪唔係最大囉。tvb now,tvbnow,bttvb& [. y5 k+ M# d7 K! l: s
係咪甘呀，睇下先~~~作者: 道道道 時間: 2007-1-4 02:05 PM
no one will be die ha ha, because everybody have 20 pcs.:-"作者: chilamhi 時間: 2007-1-4 09:17 PM
我諗第1個人機會最大作者: kljspm 時間: 2007-1-5 01:09 AM
no.3 has the highest chance.作者: samach7262559 時間: 2007-1-5 11:28 AM 標題: 回復第 6 帖由 sitsky 所發的帖子
; w/ i* g# ^ q2 _% \
its really hard cos its not necessary to take finish the bean.公仔箱論壇( J7 r( c+ Y* y& o4 u3 O! S
but i think the anser is no2,% K" N, c2 l" Z4 C& w
he just need to take one more/less than no1.作者: kenlau2526 時間: 2007-1-11 04:07 PM
i really dont know so hard作者: fai709394 時間: 2007-1-12 09:39 AM
NO 1..if he get 20 green bean ,he is sure win作者: jackyjaijai 時間: 2007-1-13 02:26 PM
#4作者: alexegg 時間: 2007-1-13 11:43 PM
still no answer ?作者: etalon 時間: 2007-1-14 03:58 PM
:'(