put six on each side first
/ x* O8 ?- {: i6 @! C5 \4 P7 ~
; W0 i& L, {; w' k# [from the heavier six, split it to three on each side5 w# ~2 k A) `( E7 g0 f3 ~
# g9 R+ ~$ E( k9 Y7 v. }then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |